﻿ Classroom Jeopardy!®
 GAME NAME: CHAPTER FOUR MATH SINGLE JEOPARDY!®

CATEGORY 1

CATEGORY 2

CATEGORY 3

CATEGORY 4

CATEGORY 5

CATEGORY 6

 FULL SIZECATEGORY ABBREVIATEDCATEGORY Explanation
 SOLVING TWO-STEP EQUATIONS SEC. 4.1 SOLVE FOR X
 SOLVING TWO-STEP EQUATIONS SEC. 4.1 SOLVE FOR X
 SOLVING MULTI-STEP EQUATIONS SEC. 4.2 SOLVE FOR X
 SOLVING MULTI-STEP EQUATIONS SEC. 4.2 SOLVE FOR X
 EQUATIONS WITH NEGATIVE COEFFICIENTS SEC. 4.3 SOLVE FOR X
 EQUATIONS WITH NEGATIVE COEFFICIENTS SEC. 4.3 SOLVE FOR X

CLUE 1

ROW VALUE
200 POINTS

Response 1

2X + 18 = 48

X = 15

27X + 5 = 59

X = 2

3X + 2X +5 = 55

X = 10

SEVEN TIMES A NUMBER

INCREASED BY 9 IS 51

X = 6

15 - X = -8

X = 23

8X + 7 -9X = -3

X = 10

CLUE 2

ROW VALUE
400 POINTS

Response 2

5X + 25 = 75

X = 10

19X - 12 = 26

X = 2

10X + 5X + 20 = 50

X = 2

THREE TIMES A NUMBER

INCREASED BY 6 IS 96

X = 30

17 - X = 19

X = -2

52 -X = 19

X = 33

CLUE 3

ROW VALUE
600 POINTS

Response 3

9X + 19 = 100

X = 9

17X - 7 = 44

X = 3

7X -5X + 12 = 48

X = 18

THE DIFFERENCE OF EIGHT

TIMES A NUMBER AND 8 IS 72

X = 10

-X -14 = -18

X = 4

32 = 92 - 8X-4X

X = 5

CLUE 4

ROW VALUE
800 POINTS

Response 4

7X - 12 = 72

X = 12

11X + 9 = 86

X = 7

14X -9 + 6X = 51

X = 3

THE DIFFERENCE OF TWELVE

TIMES A NUMBER AND 13 IS 131

X = 12

-9X -9X + 5 = -31

X = 2

17 = 4X + 8 - 7X

X = -3

CLUE 5

ROW VALUE
1000 POINTS

Response 5

13X - 4 = 48

X = 4

21X - 21 = 168

X = 9

5X + 2X + 11 = -10

X =  -3

THE SUM OF 10X AND 21 MINUS

3X IS 70

X = 7

2X + 3X + 4X +10 = 10

X = 0

-15X -15X -15X + 15 = -30

X = 1

 CATEGORY: PERIMETER FINAL JEOPARDY!® CLUE: THE PERIMETER OF ARECTANGLE WITH LENGTH OFX + 6 AND WIDTH OF X + 2 Response: 4X + 16

 GAME NAME: CHAPTER FOUR MATH DOUBLE JEOPARDY!®

CATEGORY 1

CATEGORY 2

CATEGORY 3

CATEGORY 4

CATEGORY 5

CATEGORY 6

 FULL SIZECATEGORY ABBREVIATEDCATEGORY Explanation
 EQUATIONS WITH DISTRIBUTIVE PROPERTY SEC. 4.4 SOLVE FOR X
 EQUATIONS WITH DISTRIBUTIVE PROPERTY SEC. 4.4 SOLVE FOR X
 EQUATIONS WITH VARIABLES ON BOTH SIDES SEC. 4.5 SOLVE FOR X
 EQUATIONS WITH VARIABLES ON BOTH SIDES SEC. 4.5 SOLVE FOR X
 EQUATIONS WITH DECIMALS SEC. 4.7 SOLVE FOR X
 EQUATIONS WITH DECIMALS SEC. 4.7 SOLVE FOR X

CLUE 1

ROW VALUE
400 POINTS

Response 1

3( X + 2 ) = 36

X = 10

X + 4( X + 6 ) = -1

X = -5

3X + 4 = X + 36

X = 16

7X + 12 = 13X

X = 2

2X + 9 = 27.6

X = 9.3

4X + 12 = 17.2

X = 1.3

CLUE 2

ROW VALUE
800 POINTS

Response 2

9( X + 6 ) = 108

X = 6

3X + 2( X + 8 ) = 21

X = 1

9X - 12 = 6X + 24

X = 12

5X -8 = -2X + 6

X = 2

3X + 12 = 48.9

X = 12.3

29X - 17.5 = 107.2

X = 4.3

CLUE 3

ROW VALUE
1200 POINTS

Response 3

13( X - 3 ) = 91

X = 10

5( 2X + 3 ) -5 = -70

X = -8

67 - 6X = 3 + 2X

X = 8

7X = 3( 5X -  8 )

X = 3

18X - 2 = 55.6

X = 3.2

9X + 22 = 16.6

X = -0.6

CLUE 4

ROW VALUE
1600 POINTS

Response 4

3( 3X + 4 ) = 93

X = 9

2( X + 12 ) = -8

X = -16

2X + 2X + 19 = 5X

X = 19

2( X - 9 ) = 3( X - 6 )

X = 0

9X + 9X + 2 = 59.6

X = 3.2

7X + 7X + 21.3 = 63.3

X = 3

CLUE 5

ROW VALUE
2000 POINTS

Response 5

4( -X + 5 ) = 100

X = -20

-3( X + 4 ) = 18

X = -10

19X - 108 = 21X + 6

X = -57

5X = -3( X + 4 ) + 28

X = 2

3( 6X ) + 12 = 69.6

X = 3.2

3( 12X + 0.2 ) = 90.6

X = 2.5

 CATEGORY: PERIMETER FINAL JEOPARDY!® CLUE: THE PERIMETER OF ARECTANGLE WITH LENGTH OFX + 6 AND WIDTH OF X + 2 Response: 4X + 16